Atomic Structure Question 76
Question: The atomic number of an element having the valency shell electronic configuration $ 4s^{2}4p^{6} $ is
Options:
A) 35
B) 36
C) 37
D) 38
Show Answer
Answer:
Correct Answer: B
Solution:
Complete $ E.C.={{[Ar]}^{18}}3d^{10}4s^{2}4p^{6}. $
Hence no. of $ {e^{-}}= $ no. of protons $ =36=Z $ .
