Atomic Structure Question 76

Question: The atomic number of an element having the valency shell electronic configuration $ 4s^{2}4p^{6} $ is

Options:

A) 35

B) 36

C) 37

D) 38

Show Answer

Answer:

Correct Answer: B

Solution:

Complete $ E.C.={{[Ar]}^{18}}3d^{10}4s^{2}4p^{6}. $
Hence no. of $ {e^{-}}= $ no. of protons $ =36=Z $ .



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक