Atomic Structure Question 71
Question: In the nucleus of $ _{20}Ca^{40} $ there are [CPMT 1990; EAMCET 1991]
Options:
A) 40 protons and 20 electrons
B) 20 protons and 40 electrons
C) 20 protons and 20 neutrons
D) 20 protons and 40 neutrons
Show Answer
Answer:
Correct Answer: C
Solution:
$ P=, $ 20, mass no. A = 40 $ N=, $ A-P = $ 40-20=20 $
$ P=N=20. $
