Atomic Structure Question 71

Question: In the nucleus of $ _{20}Ca^{40} $ there are [CPMT 1990; EAMCET 1991]

Options:

A) 40 protons and 20 electrons

B) 20 protons and 40 electrons

C) 20 protons and 20 neutrons

D) 20 protons and 40 neutrons

Show Answer

Answer:

Correct Answer: C

Solution:

$ P=, $ 20, mass no. A = 40 $ N=, $ A-P = $ 40-20=20 $

$ P=N=20. $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक