Atomic Structure Question 510
Question: The uncertainty in momentum of an electron is $ 1\times {10^{-5}}kg,m/s $ . The uncertainity in its position will be $ (h=6.63\times {10^{-34}}Js) $ [Pb. CET 2000]
Options:
A) $ 5.28\times {10^{-30}}m $
B) $ 5.25\times {10^{-28}}m $
C) $ 1.05\times {10^{-26}}m $
D) $ 2.715\times {10^{-30}}m $
Show Answer
Answer:
Correct Answer: A
Solution:
Uncertainity in position $ \Delta x=\frac{h}{4\pi \times \Delta p} $
$ =\frac{6.63\times {10^{-34}}}{4\times 3.14\times (1\times {10^{-5}})} $
$ =5.28\times {10^{-30}}m $ .
