SATHEE: Atomic Structure Question 510

Atomic Structure Question 510

Question: The uncertainty in momentum of an electron is $1 \times 10^{- 5} k g, m / s$ . The uncertainity in its position will be $(h = 6.63 \times 10^{- 34} J s)$ [Pb. CET 2000]

Options:

A) $5.28 \times 10^{- 30} m$

B) $5.25 \times 10^{- 28} m$

C) $1.05 \times 10^{- 26} m$

D) $2.715 \times 10^{- 30} m$

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Answer:

Correct Answer: A

Solution:

Uncertainity in position $Δ x = \frac{h}{4 π \times Δ p}$

$= \frac{6.63 \times 10^{- 34}}{4 \times 3.14 \times (1 \times 10^{- 5})}$

$= 5.28 \times 10^{- 30} m$ .

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Atomic Structure Question 510

Question: The uncertainty in momentum of an electron is 1×10−5kg,m/s . The uncertainity in its position will be (h=6.63×10−34Js) [Pb. CET 2000]

Options:

Answer:

Solution:

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Question: The uncertainty in momentum of an electron is $1 \times 10^{- 5} k g, m / s$ . The uncertainity in its position will be $(h = 6.63 \times 10^{- 34} J s)$ [Pb. CET 2000]