Atomic Structure Question 498

Question: What is the total spin value in case of $ _{26}F{e^{3+}} $ ion-

Options:

A) + 1 or - 1

B) + 2 or - 2

C) + 2.5 or - 2.5

D) + 3 or - 3

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Answer:

Correct Answer: C

Solution:

  • Total spin = Number of unpaired $ {e^{-}}\times ( \pm \frac{1}{2} ) $ $ =5\times ( \pm \frac{1}{2} )=\pm \frac{5}{2} $


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