Atomic Structure Question 498
Question: What is the total spin value in case of $ _{26}F{e^{3+}} $ ion-
Options:
A) + 1 or - 1
B) + 2 or - 2
C) + 2.5 or - 2.5
D) + 3 or - 3
Show Answer
Answer:
Correct Answer: C
Solution:
- Total spin = Number of unpaired $ {e^{-}}\times ( \pm \frac{1}{2} ) $ $ =5\times ( \pm \frac{1}{2} )=\pm \frac{5}{2} $
