Atomic Structure Question 495

Question: Number of electrons having $ \ell +m $ value equal to zero in $ _{26}Fe $ may be

Options:

A) 13

B) 20

C) 7

D) 12

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ _{26}Fe-1s^{2},2s^{2}2p^{6},3s^{2}3p^{6},3d^{6},4s^{2} $ $ \ell +m=0 $
    $ \rightarrow $ $ \ell =0,,m=0 $ i.e. s-subshell $ \ell =1,m=-1 $ i.e. one orbital of p. $ \ell =2,m=2 $ i.e. one of d-orbital’s

Hence there are 13 of 14 electrons as in d-orbital it may be one or two electron having $ m=-2 $



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