Atomic Structure Question 495
Question: Number of electrons having $ \ell +m $ value equal to zero in $ _{26}Fe $ may be
Options:
A) 13
B) 20
C) 7
D) 12
Show Answer
Answer:
Correct Answer: A
Solution:
- $ _{26}Fe-1s^{2},2s^{2}2p^{6},3s^{2}3p^{6},3d^{6},4s^{2} $
$ \ell +m=0 $
$ \rightarrow $ $ \ell =0,,m=0 $ i.e. s-subshell $ \ell =1,m=-1 $ i.e. one orbital of p. $ \ell =2,m=2 $ i.e. one of d-orbital’s
Hence there are 13 of 14 electrons as in d-orbital it may be one or two electron having $ m=-2 $
