Atomic Structure Question 45
Question: The ratio of area covered by second orbital to the first orbital is [AFMC 2004]
Options:
A) 1 : 2
B) 1 : 16
C) 8 : 1
D) 16 : 1
Show Answer
Answer:
Correct Answer: D
Solution:
$ r_{n}\propto n^{2}:A_{n}\propto n^{4} $
$ \frac{A_2}{A_1}=\frac{n_2^{4}}{n_1^{4}}=\frac{2^{4}}{1^{4}}=\frac{16}{1}=16,:1 $
