Atomic Structure Question 45

Question: The ratio of area covered by second orbital to the first orbital is [AFMC 2004]

Options:

A) 1 : 2

B) 1 : 16

C) 8 : 1

D) 16 : 1

Show Answer

Answer:

Correct Answer: D

Solution:

$ r_{n}\propto n^{2}:A_{n}\propto n^{4} $

$ \frac{A_2}{A_1}=\frac{n_2^{4}}{n_1^{4}}=\frac{2^{4}}{1^{4}}=\frac{16}{1}=16,:1 $



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