Atomic Structure Question 447

Question: What will be de-Broglie wavelength of an electron moving with a velocity of 1.2×105,ms1

Options:

A) 6.068×109

B) 3.133×1037

C) 6.626×109

D) 6.018×107

Show Answer

Answer:

Correct Answer: C

Solution:

  • λ=hp , p=mv λ=hmv

=6.62×10349.1×1031×1.2×105 λ=6.626×109m .



NCERT Chapter Video Solution

Dual Pane