Atomic Structure Question 447
Question: What will be de-Broglie wavelength of an electron moving with a velocity of $ 1.2\times 10^{5},m{s^{-1}} $
Options:
A) $ 6.068\times {10^{-9}} $
B) $ 3.133\times {10^{-37}} $
C) $ 6.626\times {10^{-9}} $
D) $ 6.018\times {10^{-7}} $
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Answer:
Correct Answer: C
Solution:
- $ \lambda =\frac{h}{p} $ , $ p=mv $ $ \lambda =\frac{h}{mv} $
$ =\frac{6.62\times {10^{-34}}}{9.1\times {10^{-31}}\times 1.2\times 10^{5}} $ $ \lambda =6.626\times {10^{-9}}m $ .
