Atomic Structure Question 447

Question: What will be de-Broglie wavelength of an electron moving with a velocity of $ 1.2\times 10^{5},m{s^{-1}} $

Options:

A) $ 6.068\times {10^{-9}} $

B) $ 3.133\times {10^{-37}} $

C) $ 6.626\times {10^{-9}} $

D) $ 6.018\times {10^{-7}} $

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ \lambda =\frac{h}{p} $ , $ p=mv $ $ \lambda =\frac{h}{mv} $

$ =\frac{6.62\times {10^{-34}}}{9.1\times {10^{-31}}\times 1.2\times 10^{5}} $ $ \lambda =6.626\times {10^{-9}}m $ .



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक