Atomic Structure Question 430
Question: The total spin and magnetic moment for the atom with atomic number 24 are:
Options:
A) $ \pm 3,\sqrt{48}BM $
B) $ \pm 3,\sqrt{35}BM $
C) $ \pm \frac{3}{2},\sqrt{48}BM $
D) $ \pm \frac{3}{2},\sqrt{35}BM $
Show Answer
Answer:
Correct Answer: A
Solution:
- Atomic number = 24 Electronic configuration is $ 3d^{5},4s^{1} $ No. of valence $ {e^{-1}}(s)=6 $ Total spin $ =\pm \frac{1}{2}\times 6=\pm 3 $ Magnetic moment $ =\sqrt{n( n+2 )}=\sqrt{6( 6+2 )} $
$ =\sqrt{48},BM $
