Atomic Structure Question 430

Question: The total spin and magnetic moment for the atom with atomic number 24 are:

Options:

A) $ \pm 3,\sqrt{48}BM $

B) $ \pm 3,\sqrt{35}BM $

C) $ \pm \frac{3}{2},\sqrt{48}BM $

D) $ \pm \frac{3}{2},\sqrt{35}BM $

Show Answer

Answer:

Correct Answer: A

Solution:

  • Atomic number = 24 Electronic configuration is $ 3d^{5},4s^{1} $ No. of valence $ {e^{-1}}(s)=6 $ Total spin $ =\pm \frac{1}{2}\times 6=\pm 3 $ Magnetic moment $ =\sqrt{n( n+2 )}=\sqrt{6( 6+2 )} $

$ =\sqrt{48},BM $



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