Atomic Structure Question 409
Question: The kinetic and potential energy (in eV) of an electron present in third Bohr’s orbit of hydrogen atom are respectively:
Options:
A) $ -1.51.-3.02 $
B) $ 1.51,-3.02 $
C) $ -3.02,1.51 $
D) $ 1.51,-1.51 $
Show Answer
Answer:
Correct Answer: B
Solution:
- Total energy of third shell $ =\frac{-13.6}{3^{2}} $
$ =-1.51eV $ K.E. = - Total energy
$ \Rightarrow 1.51eV $
$ P.E.=2\times T.E.=-3.02eV $
