Atomic Structure Question 409

Question: The kinetic and potential energy (in eV) of an electron present in third Bohr’s orbit of hydrogen atom are respectively:

Options:

A) $ -1.51.-3.02 $

B) $ 1.51,-3.02 $

C) $ -3.02,1.51 $

D) $ 1.51,-1.51 $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Total energy of third shell $ =\frac{-13.6}{3^{2}} $

$ =-1.51eV $ K.E. = - Total energy
$ \Rightarrow 1.51eV $

$ P.E.=2\times T.E.=-3.02eV $



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