Atomic Structure Question 399

Question: The de Broglie wavelength of a car of mass 1000 kg and velocity 36 km/hr is:

Options:

A) $ 6.626\times {10^{-34}}m $

B) $ 6.626\times {10^{-38}}m $

C) $ 6.626\times {10^{-31}}m $

D) $ 6.626\times {10^{-30}}m $

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ \lambda =\frac{h}{mv} $

$ h=6.6\times {10^{-34}}J-s $

$ m=1000kg $

$ v=36km/hr=\frac{36\times 10^{3}}{60\times 60}m/sec=10m/sec $
$ \therefore \lambda =\frac{6.6\times {10^{-34}}}{10^{3}\times 10}=6.6\times {10^{-38}}m $



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