Atomic Structure Question 399
Question: The de Broglie wavelength of a car of mass 1000 kg and velocity 36 km/hr is:
Options:
A) $ 6.626\times {10^{-34}}m $
B) $ 6.626\times {10^{-38}}m $
C) $ 6.626\times {10^{-31}}m $
D) $ 6.626\times {10^{-30}}m $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \lambda =\frac{h}{mv} $
$ h=6.6\times {10^{-34}}J-s $
$ m=1000kg $
$ v=36km/hr=\frac{36\times 10^{3}}{60\times 60}m/sec=10m/sec $
$ \therefore \lambda =\frac{6.6\times {10^{-34}}}{10^{3}\times 10}=6.6\times {10^{-38}}m $
