Atomic Structure Question 388

Question: The wave number of the first emission line in the Balmer series of H-Spectrum is: (R = Rydberg constant):

Options:

A) $ \frac{5}{36}R $

B) $ \frac{9}{400}R $

C) $ \frac{7}{6}R $

D) $ \frac{3}{4}R $

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Answer:

Correct Answer: A

Solution:

  • $ \overline{v}=RZ^{2}( \frac{1}{2^{2}}-\frac{1}{3^{2}} ) $

$ =R( \frac{1}{4}-\frac{1}{9} )=\frac{5R}{36} $



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