Atomic Structure Question 388
Question: The wave number of the first emission line in the Balmer series of H-Spectrum is: (R = Rydberg constant):
Options:
A) $ \frac{5}{36}R $
B) $ \frac{9}{400}R $
C) $ \frac{7}{6}R $
D) $ \frac{3}{4}R $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \overline{v}=RZ^{2}( \frac{1}{2^{2}}-\frac{1}{3^{2}} ) $
$ =R( \frac{1}{4}-\frac{1}{9} )=\frac{5R}{36} $
