SATHEE: Atomic Structure Question 367

Atomic Structure Question 367

Question: The orbital angular momentum of an electron in $2 s$ -orbital is

Options:

A) $\frac{1}{2} \frac{h}{2 π}$

B) $\frac{h}{2 π}$

C) $\sqrt{2} \frac{h}{2 π}$

D) Zero

Show Answer

Answer:

Correct Answer: D

Solution:

Since s-orbital have $l = 0$ Angular momentum = $\sqrt{l, (l + 1)} \times \frac{h}{2 π}$ = $0 \times \frac{h}{2 π} = 0$ .

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