Atomic Structure Question 367
Question: The orbital angular momentum of an electron in $ 2s $ -orbital is
Options:
A) $ \frac{1}{2}\frac{h}{2\pi } $
B) $ \frac{h}{2\pi } $
C) $ \sqrt{2}\frac{h}{2\pi } $
D) Zero
Show Answer
Answer:
Correct Answer: D
Solution:
Since s-orbital have $ l=0 $ Angular momentum = $ \sqrt{l,(l+1)}\times \frac{h}{2\pi } $ = $ 0\times \frac{h}{2\pi }=0 $ .
