Atomic Structure Question 34

Question: The radius of first Bohr-s orbit for hydrogen is $ 0.53,{\AA} $ . The radius of third Bohr’s orbit would be

Options:

A) $ 0.79{\AA} $

B) $ 1.59{\AA} $

C) $ 3.18{\AA}~~~ $

D) $ 4.77{\AA} $

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Answer:

Correct Answer: D

Solution:

$ r_{n}=r_1\times n^{2} $

$ r_3=0.53\times 3^{2} $

$ =0.53\times 9=4.77{\AA} $



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