Atomic Structure Question 34
Question: The radius of first Bohr-s orbit for hydrogen is $ 0.53,{\AA} $ . The radius of third Bohr’s orbit would be
Options:
A) $ 0.79{\AA} $
B) $ 1.59{\AA} $
C) $ 3.18{\AA}~~~ $
D) $ 4.77{\AA} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ r_{n}=r_1\times n^{2} $
$ r_3=0.53\times 3^{2} $
$ =0.53\times 9=4.77{\AA} $
