Atomic Structure Question 301

Question: Which of the following set of quantum numbers is correct for the 19th electron of chromium [DCE 2001]

Options:

A) n-3 l-0 m-0 s- 1/2

B) n-3 l-2 m- 1 2 s- 1/2

C) n-4 l-0 m- 0 s- ½

D) n-4 l-1 m- 1 s- ½

Show Answer

Answer:

Correct Answer: C

Solution:

19th electron of chromium is $ 4s^{1} $

$ n=4,\ l=0,\ m=0,\ s=+\frac{1}{2} $



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