Atomic Structure Question 301
Question: Which of the following set of quantum numbers is correct for the 19th electron of chromium [DCE 2001]
Options:
A) n-3 l-0 m-0 s- 1/2
B) n-3 l-2 m- 1 2 s- 1/2
C) n-4 l-0 m- 0 s- ½
D) n-4 l-1 m- 1 s- ½
Show Answer
Answer:
Correct Answer: C
Solution:
19th electron of chromium is $ 4s^{1} $
$ n=4,\ l=0,\ m=0,\ s=+\frac{1}{2} $
