SATHEE: Atomic Structure Question 24

Atomic Structure Question 24

Question: If electron falls from $n = 3$ to $n = 2$ , then emitted energy is [AFMC 1997; MP PET 2003]

Options:

A) $10.2 e V$

B) $12.09 e V$

C) $1.9 e V$

D) $0.65 e V$

Show Answer

Answer:

Correct Answer: C

Solution:

$Δ E = E_{3} - E_{2} = 13.6, [\frac{1}{{(2)}^{2}} - \frac{1}{{(3)}^{2}}] = 1.9, e V$

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Atomic Structure Question 24

Question: If electron falls from n=3 to n=2 , then emitted energy is [AFMC 1997; MP PET 2003]

Options:

Answer:

Solution:

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Question: If electron falls from $n = 3$ to $n = 2$ , then emitted energy is [AFMC 1997; MP PET 2003]