Atomic Structure Question 24
Question: If electron falls from $ n=3 $ to $ n=2 $ , then emitted energy is [AFMC 1997; MP PET 2003]
Options:
A) $ 10.2eV $
B) $ 12.09eV $
C) $ 1.9eV $
D) $ 0.65eV $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \Delta E=E_3-E_2=13.6,[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(3)}^{2}}} ]=1.9,eV $
