Atomic Structure Question 189
Question: The “spin-only” magnetic moment [in units of Bohr magnet on, ( $ {\mu_{B}} $ )] of $ N{i^{{2^{+}}}} $ in aqueous solution would be: (At. no. Ni = 28)
Options:
A) 1.73
B) 2.84
C) 4.90
D) 0
Show Answer
Answer:
Correct Answer: B
Solution:
- $ Ni=28={{[Ar]}^{18}}3d^{8}4s^{2};N{i^{2+}}={{[Ar]}^{18}}3d^{8} $
$ N{i^{2+}} $ has two unpaired electrons.
$ \therefore \mu =\sqrt{n(n+2)} $
$ =\sqrt{8}=2.84BM $
