Atomic Structure Question 189

Question: The “spin-only” magnetic moment [in units of Bohr magnet on, ( $ {\mu_{B}} $ )] of $ N{i^{{2^{+}}}} $ in aqueous solution would be: (At. no. Ni = 28)

Options:

A) 1.73

B) 2.84

C) 4.90

D) 0

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ Ni=28={{[Ar]}^{18}}3d^{8}4s^{2};N{i^{2+}}={{[Ar]}^{18}}3d^{8} $

$ N{i^{2+}} $ has two unpaired electrons.
$ \therefore \mu =\sqrt{n(n+2)} $

$ =\sqrt{8}=2.84BM $



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