Atomic Structure Question 18

Question: The energy of second Bohr orbit of the hydrogen atom is 328 kJ $ mol^{-1}$, hence the energy of fourth Bohr orbit would be [CBSE PMT 2005]

Options:

A) 41 kJ $ mol^{-1}$

B) 1312 kJ $ mol^{-1}$

C) 164 kJ $ mol^{-1}$

D) 82 kJ $ mol^{-1}$

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Answer:

Correct Answer: D

Solution:

$ \frac{E_4}{E_2}=\frac{2^{2}}{4^{2}}=\frac{4}{16}=\frac{1}{4} $ ; $ E_4=\frac{E_2}{4}=\frac{-328}{4}=-82kJ/mol. $



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