Atomic Structure Question 18
Question: The energy of second Bohr orbit of the hydrogen atom is 328 kJ $ mol^{-1}$, hence the energy of fourth Bohr orbit would be [CBSE PMT 2005]
Options:
A) 41 kJ $ mol^{-1}$
B) 1312 kJ $ mol^{-1}$
C) 164 kJ $ mol^{-1}$
D) 82 kJ $ mol^{-1}$
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{E_4}{E_2}=\frac{2^{2}}{4^{2}}=\frac{4}{16}=\frac{1}{4} $ ; $ E_4=\frac{E_2}{4}=\frac{-328}{4}=-82kJ/mol. $
