Atomic Structure Question 131
Question: The frequency of one of the lines in Paschen series of hydrogen atom is $ 2.340\times 10^{11}Hz. $ The quantum number $ n_2 $ which produces this transition is
[DPMT 2001]
Options:
A) 6
B) 5
C) 4
D) 3
Show Answer
Answer:
Correct Answer: B
Solution:
$ \overline{\nu }=\frac{1}{\lambda }=R_{H}[ \frac{1}{n_1^{2}}-\frac{1}{n_2^{2}} ] $
$ =\frac{1}{\lambda }=R_{H}[ \frac{1}{3^{2}}-\frac{1}{n_2^{2}} ]=n_2=3 $ for Paschen series.
