Atomic Structure Question 131

Question: The frequency of one of the lines in Paschen series of hydrogen atom is $ 2.340\times 10^{11}Hz. $ The quantum number $ n_2 $ which produces this transition is

[DPMT 2001]

Options:

A) 6

B) 5

C) 4

D) 3

Show Answer

Answer:

Correct Answer: B

Solution:

$ \overline{\nu }=\frac{1}{\lambda }=R_{H}[ \frac{1}{n_1^{2}}-\frac{1}{n_2^{2}} ] $

$ =\frac{1}{\lambda }=R_{H}[ \frac{1}{3^{2}}-\frac{1}{n_2^{2}} ]=n_2=3 $ for Paschen series.



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