Atomic Structure Question 118
Question: The ratio of the energy of a photon of $ 2000{\AA} $ wavelength radiation to that of $ 4000{\AA} $ radiation is
Options:
A) 1/4
B) 4
C) 1/2
D) 2
Show Answer
Answer:
Correct Answer: D
Solution:
$ E=hv=h\frac{c}{\lambda }, $ i.e. $ E\propto \frac{1}{\lambda } $
$ \frac{E_1}{E_2}=\frac{{\lambda_2}}{{\lambda_1}}=\frac{4000}{2000}=2. $
