Atomic Structure Question 118

Question: The ratio of the energy of a photon of $ 2000{\AA} $ wavelength radiation to that of $ 4000{\AA} $ radiation is

Options:

A) 1/4

B) 4

C) 1/2

D) 2

Show Answer

Answer:

Correct Answer: D

Solution:

$ E=hv=h\frac{c}{\lambda }, $ i.e. $ E\propto \frac{1}{\lambda } $

$ \frac{E_1}{E_2}=\frac{{\lambda_2}}{{\lambda_1}}=\frac{4000}{2000}=2. $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक