Shortcut Methods
JEE Main
Circular Disc (Rolling): Angular Momentum = $$150 kg.m^2/s$$ _Use $$ I=\frac{1}{2}MR^2 $$, angular momentum equation: $$ L=I\omega$$ _
Solid Sphere (Rolling): Angular Momentum = $$8.33 kg.m^2/s$$ _Use $$ I=\frac{2}{5}MR^2. $$, angular momentum equation: $$ L=I\omega $$ _
Two Particles (Rotating): Angular Momentum = $$10 kg.m^2/s$$ Use $$ I = m_1r_1^2 + m_2r_2^2+…$$angular momentum equation: $$ L=I\omega $$
CBSE Board Exams
Circular Disc (Rotating): Angular Momentum = $$20 kg.m^2/s$$ Use $$ I=\frac{1}{2}MR^2$$, angular momentum equation: $$ L=I\omega $$
Solid Cylinder (Rolling): Angular Momentum = $$4.24 kg.m^2/s$$ _Use $$ I=\frac{1}{2}MR^2 $$angular momentum equation: $$ L=I\omega $$ _
Two Particles (Rotating): Angular Momentum = $$2.5 kg.m^2/s$$ Use $$ I = m_1r_1^2 + m_2r_2^2 +…$$, angular momentum equation: $$ L=I\omega$$
