SATHEE: Shortcut Methods

Shortcut Methods

Integer Type Numericals for JEE (Advanced):

1. Centripetal acceleration: $a_{c} = \frac{v^{2}}{r} = \frac{(10 m / s)^{2}}{5 m} = 20 m / s^{2}$

2. Centripetal acceleration: $a_{c} = \frac{v^{2}}{r} = \frac{(36 k m / h)^{2}}{(100 m)} = 12.96 m / s^{2}$

3. Angular velocity: $ω = \frac{2 π}{T} = \frac{2 π r a d}{5 s} = 1.257 r a d / s$

4. Linear speed: $v = r ω = (10 m) (2 r a d / s) = 20 m / s$

5. Angular velocity: $ω = \frac{2 π N}{60} = \frac{2 π (600 r p m)}{60} = 62.83 r a d / s$

Integer Type Numericals for JEE (Main):

1. Centripetal acceleration: $a_{c} = \frac{v^{2}}{r} = \frac{(5 m / s)^{2}}{2 m} = 12.5 m / s^{2}$

2. Centripetal acceleration: $a_{c} = \frac{v^{2}}{r} = \frac{(18 k m / h)^{2}}{(50 m)} = 6.48 m / s^{2}$

3. Angular velocity: $ω = \frac{2 π}{T} = \frac{2 π r a d}{10 s} = 0.628 r a d / s$

4. Linear speed: $v = r ω = (5 m) (1 r a d / s) = 5 m / s$

5. Angular velocity: $ω = \frac{2 π N}{60} = \frac{2 π (300 r p m)}{60} = 31.42 r a d / s$

Integer Type Numericals for CBSE (Class 11 and 12):

1. Centripetal acceleration: $a_{c} = \frac{v^{2}}{r} = \frac{(2 m / s)^{2}}{1 m} = 4 m / s^{2}$

2. Centripetal acceleration: $a_{c} = \frac{v^{2}}{r} = \frac{(9 k m / h)^{2}}{(25 m)} = 3.24 m / s^{2}$

3. Angular velocity: $ω = \frac{2 π}{T} = \frac{2 π r a d}{20 s} = 0.314 r a d / s$

4. Linear speed: $v = r ω = (2 m) (0.5 r a d / s) = 1 m / s$

5. Angular velocity: $ω = \frac{2 π N}{60} = \frac{2 π (150 r p m)}{60} = 15.71 r a d / s$

Shortcut Methods

Shortcut Methods

Table of Contents

Engineering Preparation

Mathematics 11th

Mathematics 12th

JEE Previous Year Questions

JEE Tutorial Sessions

Medical Preparation

NEET Previous Year Questions

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