SATHEE: Shortcut Methods

Shortcut Methods

JEE Main Level:

Numerical 1:
- Shortcut Method: $f_{r} = \frac{1}{2 π} (\sqrt{1 / L_{1}} + \sqrt{1 / L_{2}})$

$f_{r} = \frac{1}{2 π} \sqrt{\frac{1}{L C} (\frac{L_{1} + L_{2}}{L_{1} L_{2}})}$

$f_{r} = \frac{1}{2 π \sqrt{(100 mH) (100 μ F)}}$

Numerical 2:
- Shortcut Method:

$Q = \frac{ω_{r e s} L}{R} = \frac{1}{R} \sqrt{\frac{L}{C}}$

CBSE Board Level:

Numerical 1:
- Shortcut Method: Resonant current $I_{r} e s = \frac{V}{R} : Q : V_{m}$

$I_{r} e s = \frac{V}{R}$

Numerical 2:
- Shortcut Method: $Q = \frac{ω_{r e s} L}{R} = \frac{V_{C}}{I R}$

$V_{C} = Q I_{r} = \frac{ω_{r e s} L}{R}$

Shortcut Methods

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Shortcut Methods

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