Shortcut Methods
JEE Mains/Advanced
1.
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Wavelength (λ): λ = 2π/k
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Frequency (f): f = ω/2π
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Speed (v): v = ω/k
2.
- Wavelength (λ): λ = v/f = 300 m/s / 50 Hz = 6 m
3.
- Speed (v): v = √(T/μ) = √(100 N / 0.01 kg/m) = 100 m/s
4.
- Transmitted wave amplitude: 0.5 m (since the wave is partially reflected and partially transmitted)
5.
- Diffraction angle (θ): θ = sin^(-1)(λ/d) = sin^(-1)(2λ/d)
CBSE Board Exams
1.
- A: amplitude of the wave
- k: wave number (k = 2π/λ)
- ω: angular frequency (ω = 2πf)
2.
- Wavelength (λ): λ = v/f = 300 m/s / 50 Hz = 6 m
3.
- Speed (v): v = √(T/μ) = √(100 N / 0.01 kg/m) = 100 m/s
4.
- When a wave pulse reaches a boundary between two media with different densities, part of the wave is reflected and part is transmitted. The amount of reflection and transmission depends on the difference in densities of the two media.
5.
- When a wave encounters an obstacle with a small opening, the wave bends around the edges of the opening due to diffraction. This is because the wavefronts of the wave spread out as they pass through the opening, causing the wave to bend around the obstacle.
