Shortcut Methods


JEE Main Level

  • For vertical motion problems, use the equation of motion: $$h_{max} = v_i^2/2g$$ where $$h_{max}$$ is the maximum height, $$v_i$$ is the initial velocity, and $$g$$ is the acceleration due to gravity.

  • For collisions in one dimension, use the conservation of momentum: $$m_1v_1 + m_2v_2 = m_1u_1 + m_2u_2$$ where $$m_1$$ and $$m_2$$ are the masses of the two objects, $$v_1$$ and $$v_2$$ are their initial velocities, and $$u_1$$ and $$u_2$$ are their final velocities.

  • For collisions in two dimensions, use the conservation of momentum in both the $$x$$ and $$y$$ directions. Also, consider the energy balance equation $$E_i=E_f$$ or $$K_i=K_f$$ in the case of elastic collision.

CBSE Board Level

  • Use the same formulas and principles as for the JEE Main level, but the problems may be simpler and involve smaller values.

Typical Questions

  • To find the height reached by a ball thrown vertically upwards, use the formula: $$h_{max} = v_i^2/2g$$

  • To find the velocity of a ball after collision with another ball at rest, use the conservation of momentum: $$v_{2f} = (2m_1v_1)/(m_1 + m_2)$$

  • To find the velocity of a car after collision with a truck at rest, use the conservation of momentum: $$v_{1f} = \frac{M-2 m}{M+m} v_1$$


Additional Tips

  • Draw diagrams to visualize the problem. This can help you to identify the forces involved and the directions of motion.

  • Break down the problem into smaller steps. This can make it easier to find a solution.

  • Be careful with units. Make sure to use consistent units throughout the problem.

  • Don’t forget to check your answer. This is especially important for more complex problems.