Shortcut Methods

JEE Advanced:

1. A spring-mass system with a mass of 0.1 kg and a spring constant of 100 N/m is set into oscillation with an amplitude of 0.1 m.

Solution:

  • Period (T): T=2πmk
    =2π0.1 kg100 N/m =0.628 s

  • Frequency (f): f=1T =10.628 s =1.59 Hz

2. A simple pendulum with a length of 1 m is set into oscillation with an amplitude of 10 degrees.

Solution:

  • Period (T): T=2πLg
    =2π1 m9.81 m/s2 =2.01 s

  • Frequency (f): f=1T =12.01 s =0.498 Hz

3. A block of mass 2 kg is attached to a spring of spring constant 500 N/m. The block is displaced from its equilibrium position by 10 cm and released. Find the amplitude, period, and frequency of oscillation.

Solution:

  • Amplitude (A): A=10 cm=0.1 m

  • Period (T): T=2πmk
    =2π2 kg500 N/m =0.632 s

  • Frequency (f): f=1T =10.632 s =1.58 Hz

CBSE Board:

1. A mass of 0.5 kg is attached to a spring with a spring constant of 100 N/m. The mass is set into oscillation with an amplitude of 0.2 m. Calculate the period of oscillation.

Solution:

  • Period (T): T=2πmk
    =2π0.5 kg100 N/m =1.13 s

2. A simple pendulum with a length of 0.8 m is set into oscillation. If the time taken for 10 oscillations is 16 seconds, calculate the amplitude of oscillation.

Solution:

  • Period (T) for 10 oscillations: T10=16 s

  • Period (T) for 1 oscillation: T=T1010 =16 s10 =1.6 s

  • Amplitude (A): T=2πLg 1.6 s=2π0.8 mg A=0.16 m

3. A mass of 1 kg is attached to a spring of spring constant 200 N/m. The block is displaced from its equilibrium position by 5 cm and released. Determine the amplitude, period, and frequency of oscillation.

Solution:

  • Amplitude (A): A=5 cm=0.05 m

  • Period (T): T=2πmk
    =2π1 kg200 N/m =0.444 s

  • Frequency (f): f=1T =10.444 s =2.25 Hz



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