Shortcut Methods
JEE Mains:
- Find the area of the circle with radius ‘r’.
Area = πr²
- Find the circumference of the circle with radius ‘r’.
Circumference = 2πr
- Find the equation of the circle with center ‘(a, b)’ and radius ‘r’.
(x - a)² + (y - b)² = r²
- Find the equation of the tangent to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.
y - y₁ = (x - x₁) * [(y₁ - b)/(x₁ - a)]
- Find the equation of the normal to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.
y - y₁ = [(x₁ - a)/(y₁ - b)] * (x - x₁)
- Find the length of the chord of the circle with center ‘(a, b)’ and radius ‘r’ that passes through the points ‘(x1, y1)’ and ‘(x2, y2)’.
Length of chord = √((x₂ - x₁)² + (y₂ - y₁)²)
- Find the area of the sector of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.
Area of sector = (θ/360) * πr²
- Find the length of the arc of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.
Length of arc = (θ/360) * 2πr
CBSE Board Exams:
- Find the area of the circle with radius ‘r’.
Area = πr²
- Find the circumference of the circle with radius ‘r’.
Circumference = 2πr
- Find the equation of the circle with center ‘(a, b)’ and radius ‘r’.
(x - a)² + (y - b)² = r²
- Find the equation of the tangent to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.
(x - x₁)² + (y - y₁)² = r²
- Find the equation of the normal to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.
2x(x - x₁) + 2y(y - y₁) = r²
- Find the length of the chord of the circle with center ‘(a, b)’ and radius ‘r’ that passes through the points ‘(x1, y1)’ and ‘(x2, y2)’.
Length of chord = √((x₂ - x₁)² + (y₂ - y₁)²)
- Find the area of the sector of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.
Area of sector = (θ/360) * πr²
- Find the length of the arc of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.
Length of arc = (θ/360) * 2πr
- Find the area of the segment of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.
Area of segment = Area of sector - Area of triangle formed by radii and chord =(θ/360) * πr² - (1/2) * r² * sinθ