Shortcut Methods

JEE Mains:


  • Find the area of the circle with radius ‘r’.

Area = πr²

  • Find the circumference of the circle with radius ‘r’.

Circumference = 2πr

  • Find the equation of the circle with center ‘(a, b)’ and radius ‘r’.

(x - a)² + (y - b)² = r²

  • Find the equation of the tangent to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.

y - y₁ = (x - x₁) * [(y₁ - b)/(x₁ - a)]

  • Find the equation of the normal to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.

y - y₁ = [(x₁ - a)/(y₁ - b)] * (x - x₁)

  • Find the length of the chord of the circle with center ‘(a, b)’ and radius ‘r’ that passes through the points ‘(x1, y1)’ and ‘(x2, y2)’.

Length of chord = √((x₂ - x₁)² + (y₂ - y₁)²)

  • Find the area of the sector of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.

Area of sector = (θ/360) * πr²

  • Find the length of the arc of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.

Length of arc = (θ/360) * 2πr

CBSE Board Exams:


  • Find the area of the circle with radius ‘r’.

Area = πr²

  • Find the circumference of the circle with radius ‘r’.

Circumference = 2πr

  • Find the equation of the circle with center ‘(a, b)’ and radius ‘r’.

(x - a)² + (y - b)² = r²

  • Find the equation of the tangent to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.

(x - x₁)² + (y - y₁)² = r²

  • Find the equation of the normal to the circle with center ‘(a, b)’ and radius ‘r’ at the point ‘(x1, y1)’.

2x(x - x₁) + 2y(y - y₁) = r²

  • Find the length of the chord of the circle with center ‘(a, b)’ and radius ‘r’ that passes through the points ‘(x1, y1)’ and ‘(x2, y2)’.

Length of chord = √((x₂ - x₁)² + (y₂ - y₁)²)

  • Find the area of the sector of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.

Area of sector = (θ/360) * πr²

  • Find the length of the arc of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.

Length of arc = (θ/360) * 2πr

  • Find the area of the segment of the circle with center ‘(a, b)’ and radius ‘r’ that is subtended by the central angle ‘θ’.

Area of segment = Area of sector - Area of triangle formed by radii and chord =(θ/360) * πr² - (1/2) * r² * sinθ



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