Related Problems with Solutions
Problem 2 : For the reaction A(g) → B(g) at 300 K, the equilibrium constant (Kc) is 0.1. Calculate the standard Gibbs free energy change (∆G°) for this reaction.
Solution :
The relationship between ∆G° and Kc is given by the equation: ∆G° = -RT ln(Kc)
Given that Kc = 0.1 and T = 300 K, you can calculate ∆G°:
∆G° = -8.314 J/(mol•K) * 300 K * ln(0.1) ∆G° ≈ -8.314 J/(mol•K) * 300 K * (-2.3026)
∆G° ≈ 5547.84 J/mol ≈ 5.55 kJ/mol
