- 2019:
Given,
P1 = 2 atm, T1 = 27 °C = 300 K, V2 = 4V1
We know that,
PV = nRT
So,
P1V1 = n1RT1
P2V2 = n2RT2
Since n1 = n2, we can write,
P1V1 = P2V2
Substituting the values, we get
2 * V1 = P2 * 4V1
or,
P2 = 1 atm
Also,
T2 = T1 * (V2/V1) = 300 * (4/1) = 1200 K
So, the final temperature and pressure of the gas will be 300 K and 1 atm.
- 2018:
We know that,
W = -PΔV