• 2019:

Given,

P1 = 2 atm, T1 = 27 °C = 300 K, V2 = 4V1

We know that,

PV = nRT

So,

P1V1 = n1RT1
P2V2 = n2RT2

Since n1 = n2, we can write,

P1V1 = P2V2

Substituting the values, we get

2 * V1 = P2 * 4V1

or,

P2 = 1 atm

Also,

T2 = T1 * (V2/V1) = 300 * (4/1) = 1200 K

So, the final temperature and pressure of the gas will be 300 K and 1 atm.

  • 2018:

We know that,

W = -PΔV