Motion

  1. A particle moves along a straight line such that its displacement at any time t is given by $x = 6t + 4t^2$. The average velocity of the particle between t = 2s and t = 4s is:

(A) 10 m/s (B) 12 m/s (C) 14 m/s (D) 16 m/s

Let’s think step-by-step.

Average velocity = $\frac{Displacement}{Time}$

$Average\ velocity = \frac{x(4)-x(2)}{4-2} = \frac{24-12}{2} = 6 m/s$

The final answer: (A).