- 2019: A compound with molecular formula C6H12O2 gives iodoform test and forms 2,4-DNP derivative. On reduction with LiAlH4, it gives a sweet smelling compound. The compound is:
(A) Acetone (B) Propan-2-one (C) Propanal (D) Butanal
Answer: (A) Acetone Explanation:
The molecular formula C6H12O2 matches the formula for acetone (CH3COCH3). The compound gives a positive iodoform test because it contains a methyl ketone group (CH3CO-). The compound forms a 2,4-DNP derivative because it contains an aldehyde group (-CHO). The compound is reduced to a sweet smelling compound, 2-propanol (CH3CH2CH2OH), with LiAlH4.
- 2018: Which of the following compounds does not undergo aldol condensation?
(A) Propanal (B) Benzaldehyde (C) Acetaldehyde (D) Trichloroacetaldehyde
Answer: (D) Trichloroacetaldehyde
