SATHEE: PYQ NEET- Electromagnetic Waves L-1

Question: In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10} Hz$ and amplitude $48 {Vm}^{- 1}$ . Then the amplitude of oscillating magnetic field is : (Speed of light in free space $= 3 \times 10^{8} m s^{- 1}$ ): (NEET-2023)

A) $1.6 \times 10^{- 8} T$

B) $1.6 \times 10^{- 7} T$

C) $1.6 \times 10^{- 6} T$

D) $1.6 \times 10^{- 9} T$

Answer: $1.6 \times 10^{- 7} T$

Explanation

$C = \frac{E_{0}}{B_{0}}$

$B_{0} = \frac{E_{0}}{C}$

$= \frac{48}{3 \times 10^{8}}$

$= 1.6 \times 10^{- 7} T$

Play Store

App Store

The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Question: In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0×1010 Hz and amplitude 48Vm−1. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s−1 ): (NEET-2023)

Answer: 1.6×10−7 T

Explanation

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Mentorship

NCERT Exercise Video Solution

Menu

Answer: $1.6 \times 10^{- 7} T$